- Problem 1 A Short Tied Column Shown Is To Support The Following Loads Below Use F C 27 Mpa And Fy 400 Mpa Concrete Co 1 (25.78 KiB) Viewed 11 times
Problem 1: A short tied column shown is to support the following loads below. Use f'c-27 MPa and fy=400 MPa. Concrete co
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Problem 1: A short tied column shown is to support the following loads below. Use f'c-27 MPa and fy=400 MPa. Concrete co
Problem 1: A short tied column shown is to support the following loads below. Use f'c-27 MPa and fy=400 MPa. Concrete cover is 40 mm. Use 12mm diameter ties. Dead load = 900 KN Live load = 600 KN Wind load 800 KN Roof live load 600 KN Earthquake load = 1600 KN Rain load 700 KN 1. Calculate the design axial load of the column. 2. Determine the required the minimum required "B" if the steel ratio is limited to 3%. 3. Determine the required number of 32 mm diameter bars and sketch the arrangement of the bars. FACTORED LOADS DEFINITIONS Odead load weight of ice arthquake load ACI INSCP 41U14D F ACI 9-3NSCP 409-2 U-120 FT) 1.6L H0L or S or ACIS-SNSOP 409-3 U 1.20 1.4L or Sor R) (1.0L or 0.8W) ACS-ANSCP 4004 U-120+1.0W+10L0L, or or AC-SNSCP 400-5 U 1.20 ACI 9-6NSCP 409-6U-0.50 AC-INSCP 409-7 U-0.30 Fload due to fluids with well-defined pressures and maximum heights F. food load 1.0E+10+0.25 1.5W+1H 1.0E+1GH Hload due to lateral earth pressure, ground water pressure, or pressure of buk materials Live load L roof live load R=rain load 5-snow load Te self-straning force W wind load W wind on ice determined in accordance with Chapter 10