- And K 0 6 The Circuit In Figure 13 Operates At Frequency 10 Rud Sec In Steady State Condition The Phasor Of The Inpu 1 (78.31 KiB) Viewed 15 times
- And K 0 6 The Circuit In Figure 13 Operates At Frequency 10 Rud Sec In Steady State Condition The Phasor Of The Inpu 2 (57.47 KiB) Viewed 15 times
and k=0.6. The circuit in Figure 13 operates at frequency = 10 rud/sec in steady state condition. The phasor of the input voltage, V, is 30/0 a) Find and draw the Norton equivalent circuit seen between terminals a and b. b) Find the optimal value of the impedance Z, so that the maximum power is transferred to the load, then find the maximum delivered power to the load and draw the circuit with the derived values of the Norton equivalent circuit (from part a) and the optimal Z₁. c) Now the sinusoidal voltage source is disconnected from the circuit in Figure 13 and replaced with a constant voltage source of amplitude 12 Volts, in series with a switch (see Figure 14). Initial energy of the circuit is zero. The switch is closed at t=0. Construct the s-domain equivalent of the circuit in Figure 13, and find the s-domain expression for the Norton equivalent circuit between terminals a and b.
Vs Figure 13 요 Vs Figure 14 10Ω 01- 1 100 j4 a kl Z₁ b Norton Equivalent j4 m a %₂ kl b Norton Equivalent