The time-independent Schrodinger equation for a particle that
executes rotational motion in two dimensions (particle in the ring)
is:
The Time Independent Schrodinger Equation For A Particle That Executes Rotational Motion In Two Dimensions Particle In 1 (4.02 KiB) Viewed 21 times
Consider the following wave function of the particle in the
ring.
The Time Independent Schrodinger Equation For A Particle That Executes Rotational Motion In Two Dimensions Particle In 2 (2.96 KiB) Viewed 21 times
1. Is this wave function an eigenfunction of the H
Hamiltonian operator?
2. If it is, what is the value of the corresponding energy of the
particle?
3. Is it a proper function of the Lz angular momentum operator
?
Selec the correct response: *comment the premises of
each question according to the choice shown*
The Time Independent Schrodinger Equation For A Particle That Executes Rotational Motion In Two Dimensions Particle In 3 (1.15 KiB) Viewed 21 times
f. if it is a proper function of the angular momentum operator
g. it cannot be determined if it is an eigenfunction
The Time Independent Schrodinger Equation For A Particle That Executes Rotational Motion In Two Dimensions Particle In 4 (1.79 KiB) Viewed 21 times
The Time Independent Schrodinger Equation For A Particle That Executes Rotational Motion In Two Dimensions Particle In 5 (886 Bytes) Viewed 21 times
The Time Independent Schrodinger Equation For A Particle That Executes Rotational Motion In Two Dimensions Particle In 6 (1.17 KiB) Viewed 21 times
The Time Independent Schrodinger Equation For A Particle That Executes Rotational Motion In Two Dimensions Particle In 7 (1.14 KiB) Viewed 21 times
l. is not a proper function of the Hamiltonian operator
– h² d² = 2m dø24(Q) = Ey(0)
¥(0) = A (sin – coso) =
2 62 2m
(c)(x) * *
M2h2 2mL2
(中)
1 2 ko 2 5 kº?
h2 2m
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