Answer Happy

Two different visible lights are used separately in a double
slit interference experiment. The wavelengths of the lights
are λ1=λ1= nmnm and λ2=λ2= nmnm.
The distance between aperture and viewing screens
is mm and slits are separated by mmmm.
Consider the angle θθ is small.
Problem 7(11 points) For parts a), b), and c) of the below question, fill in the empty boxes with your answer (YOUR ANSWER MUST BE ONLY A NUMBER; DO NOT WRITE UNITS; DO NOT WRITE LETTERS). Two different visible lights are used separately in a double slit interference experiment. The wavelengths of the lights are 11 = 451 nm and 12 = 665 nm. The distance between aperture and viewing screens is 2.969 m and slits are separated by 0.6269 mm. Consider the angle is small a) [1 point] Which formula can be used to calculate the location of a bright fringe on the viewing screen? (refer to the formula sheet and select the number of the correct formula from the list) b) [5 points) Find the separation distance between the second order bright fringe where the wavelength is in and the second order bright fringe where the wavelength is 12. Ду = m m1 -? m, and my are bright fringe numbers for 11 and 12, respectively. c) [5 points) Let us assume that the interference patterns due to the wavelengths 14 = 451 nm and 12 = 665 nm are overlapping. What is the ratio of m2 mi = m2