Two different visible lights are used separately in a double slit interference experiment. The wavelengths of the lights

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Two different visible lights are used separately in a double
slit interference experiment. The wavelengths of the lights
are λ1=λ1= nmnm and λ2=λ2= nmnm.
The distance between aperture and viewing screens
is mm and slits are separated by mmmm.
Consider the angle θθ is small.

Two Different Visible Lights Are Used Separately In A Double Slit Interference Experiment The Wavelengths Of The Lights 1 (62.02 KiB) Viewed 18 times

Problem 7(11 points) For parts a), b), and c) of the below question, fill in the empty boxes with your answer (YOUR ANSWER MUST BE ONLY A NUMBER; DO NOT WRITE UNITS; DO NOT WRITE LETTERS). Two different visible lights are used separately in a double slit interference experiment. The wavelengths of the lights are 11 = 451 nm and 12 = 665 nm. The distance between aperture and viewing screens is 2.969 m and slits are separated by 0.6269 mm. Consider the angle is small a) [1 point] Which formula can be used to calculate the location of a bright fringe on the viewing screen? (refer to the formula sheet and select the number of the correct formula from the list) b) [5 points) Find the separation distance between the second order bright fringe where the wavelength is in and the second order bright fringe where the wavelength is 12. Ду = m m1 -? m, and my are bright fringe numbers for 11 and 12, respectively. c) [5 points) Let us assume that the interference patterns due to the wavelengths 14 = 451 nm and 12 = 665 nm are overlapping. What is the ratio of m2 mi = m2