total volume: 300ml. Results. 2ml.→ SEED BLANIZ 5ml STANDARD 0.5ml SHAMPOO ALT Date: Page: final DO 7.625mg/L 8:24mg/L.

[answerhappygod]

Total Volume 300ml Results 2ml Seed Blaniz 5ml Standard 0 5ml Shampoo Alt Date Page Final Do 7 625mg L 8 24mg L 1 (106.78 KiB) Viewed 16 times

total volume: 300ml. Results. 2ml.→ SEED BLANIZ 5ml STANDARD 0.5ml SHAMPOO ALT Date: Page: final DO 7.625mg/L 8:24mg/L. 6.825 mg/L 8.5mg/L 8.535 m/ 7.695 mg/ glutamic acid (HO₂ CCH₂ CH₂ CH (NH₂) CO₂ H) Zul of Seed in each. Initial Initial DO STANDAID = glucose (C6H₁₂ Os)

a Answer the following questions. Include your full working out where relevant. i. Determine the BOD of the seed blank (i.e. using the seed blank as a 'sample'), standard glucose and glutamic acid and shampoo samples provided to your group. Show your full working out in your report. Hint: don't forget to include the dilution of the original shampoo sample you were given 6 marks) ii. Determine the Theoretical Oxygen Demand (THOD) value based on chemical stoichiometry for your standard glucose (C6H1206) and glutamic acid (HO2CCH2CH2CH(NH2)CO2H) sample. Hint: include the carbonaceous THOD and nitrogenous THOD. Show full working out in your report. (5 marks) iii. For your standard glucose and glutamic acid sample, compare and discuss the BOD you obtained with the ThOD sample. (2 marks) iv. Could you estimate the BOD of your shampoo sample using ThOD? Explain why. (2 marks)