A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas of 3,473 and 10.222, respectively, in

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A Solution Containing 3 47 Mm X Analyte And 1 72 Mm S Standard Gave Peak Areas Of 3 473 And 10 222 Respectively In 1 (11.38 KiB) Viewed 82 times

A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas of 3,473 and 10.222, respectively, in a chromatographic analysis. Then 1.00 ml. of 8.47 mM S was added to 5.00 mL of unknown X, and the mixture was diluted to 10.0 mL.. This solution gave peak areas of 5,428 and 4,431 for X and S. respectively. Find the concentration of X in the original unknown. DA-12.3X10-3M 0824.6 x 10-3 M OC6.15 x 103 M D12.3 x 102 M