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Salicylaldehyde reacts with diethyl zinc in a 1:1 ratio to form compound A according to the following scheme: OH O + Etz

Posted: Sun May 22, 2022 6:43 pm
by answerhappygod
Salicylaldehyde Reacts With Diethyl Zinc In A 1 1 Ratio To Form Compound A According To The Following Scheme Oh O Etz 1
Salicylaldehyde Reacts With Diethyl Zinc In A 1 1 Ratio To Form Compound A According To The Following Scheme Oh O Etz 1 (91.65 KiB) Viewed 11 times
g. A reacts cleanly with Me3SiCl to form compound D, with
molecular weight 194, a colourless crystalline solid, E, and
reform some Et2Zn. Identify D and E using
the available data, and explain why this is the sole
product. [4 marks]
Salicylaldehyde reacts with diethyl zinc in a 1:1 ratio to form compound A according to the following scheme: OH O + EtzZn A + gas On cooling, compound B crystallises from solution, and half an equivalent of diethyl zinc is found to have reformed in solution. А B + 0.5 Et Zn d. Identify A, B, and the gas. [3 marks) e. By what process does A transform to B? Sketch a plausible intermediate. [2 marks] f. A reacts cleanly with anhydrous HCl to release a gas and form compound C. Identify C, and explain why this is the sole product. [2 marks]