Salicylaldehyde reacts with diethyl zinc in a 1:1 ratio to form compound A according to the following scheme: OH O + Etz

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

Salicylaldehyde reacts with diethyl zinc in a 1:1 ratio to form compound A according to the following scheme: OH O + Etz

Post by answerhappygod »

Salicylaldehyde Reacts With Diethyl Zinc In A 1 1 Ratio To Form Compound A According To The Following Scheme Oh O Etz 1
Salicylaldehyde Reacts With Diethyl Zinc In A 1 1 Ratio To Form Compound A According To The Following Scheme Oh O Etz 1 (91.65 KiB) Viewed 9 times
g. A reacts cleanly with Me3SiCl to form compound D, with
molecular weight 194, a colourless crystalline solid, E, and
reform some Et2Zn. Identify D and E using
the available data, and explain why this is the sole
product. [4 marks]
Salicylaldehyde reacts with diethyl zinc in a 1:1 ratio to form compound A according to the following scheme: OH O + EtzZn A + gas On cooling, compound B crystallises from solution, and half an equivalent of diethyl zinc is found to have reformed in solution. А B + 0.5 Et Zn d. Identify A, B, and the gas. [3 marks) e. By what process does A transform to B? Sketch a plausible intermediate. [2 marks] f. A reacts cleanly with anhydrous HCl to release a gas and form compound C. Identify C, and explain why this is the sole product. [2 marks]
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply