- Question 1 These Things May Help Ag R T In K Ag Nfe E E 0 0592 N Log Q C 2 997 108 M S R 8 314 J Mol K F 9 1 (31.83 KiB) Viewed 8 times
QUESTION 1 These things may help. AG=-R*T*In(K) AG=- nFE E = E° -0.0592/n * log Q c= 2.997*108 m/s R=8.314 J/mol-K F = 9
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QUESTION 1 These things may help. AG=-R*T*In(K) AG=- nFE E = E° -0.0592/n * log Q c= 2.997*108 m/s R=8.314 J/mol-K F = 9
QUESTION 1 These things may help. AG=-R*T*In(K) AG=- nFE E = E° -0.0592/n * log Q c= 2.997*108 m/s R=8.314 J/mol-K F = 96,485 C/mol In (Nt/No) = -kt In (1/2) = -k 1412 = E = mc2 Answer the question "I am taking test five right now." below. True False