9O2 + 2P3
yields 6PO3 What would the pressure be if
there are 2.75 moles of each gas in a 2.31 L container at 451 C at
equilibrium and then 2.5 moles of gaseous PO3 were added to the
container? Assume temperature and volume are constant
What would the new pressure inside container be?
9O2 + 2P3 yields 6PO3 What would the pressure be if there are 2.75 moles of each gas in a 2.31 L container at 451
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