3.9 Stoichiometric Calculations: Amounts of Reactants and Products This section will be explained by solving the followi

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

3.9 Stoichiometric Calculations: Amounts of Reactants and Products This section will be explained by solving the followi

Post by answerhappygod »

3 9 Stoichiometric Calculations Amounts Of Reactants And Products This Section Will Be Explained By Solving The Followi 1
3 9 Stoichiometric Calculations Amounts Of Reactants And Products This Section Will Be Explained By Solving The Followi 1 (263.91 KiB) Viewed 7 times
3 9 Stoichiometric Calculations Amounts Of Reactants And Products This Section Will Be Explained By Solving The Followi 2
3 9 Stoichiometric Calculations Amounts Of Reactants And Products This Section Will Be Explained By Solving The Followi 2 (263.91 KiB) Viewed 7 times
can u answer all the questions please I got stuck in limiting reactant the answer was equal and did not know which one is the limiting reactant.
3.9 Stoichiometric Calculations: Amounts of Reactants and Products This section will be explained by solving the following problem. C3H2(g) 1 mole + 502(g) > 3CO2(g) + 5 moles 3 moles (Always work with moles and not grams) 4H2O(g) 4 moles 1. What mass of oxygen will react with 96.1 g of propane C3H2 ? Moles of propane = 96.1 g/44.1 g = 2.18 moles Moles of oxygen = 2.18 moles C3H, x 5 moles 0/1 moles CzHg = 10.9 moles Mass of oxygen = 10.9 moles x 32g/1 mole O2 = 349 g 8 = = 2. What mass of carbon dioxide is produced when 96.1g of propane is combusted with oxygen? Moles of CO2 = 2.18 moles C2H, x 3 moles CO2/1 moles C3H, = 6.54 moles Mass of CO2 = 6.54 moles x 44g/1 moles CO2 = 288g

3.9 Stoichiometric Calculations: Amounts of Reactants and Products This section will be explained by solving the following problem. C3H2(g) 1 mole + 502(g) > 3CO2(g) + 5 moles 3 moles (Always work with moles and not grams) 4H2O(g) 4 moles 1. What mass of oxygen will react with 96.1 g of propane C3H2 ? Moles of propane = 96.1 g/44.1 g = 2.18 moles Moles of oxygen = 2.18 moles C3H, x 5 moles 0/1 moles CzHg = 10.9 moles Mass of oxygen = 10.9 moles x 32g/1 mole O2 = 349 g 8 = = 2. What mass of carbon dioxide is produced when 96.1g of propane is combusted with oxygen? Moles of CO2 = 2.18 moles C2H, x 3 moles CO2/1 moles C3H, = 6.54 moles Mass of CO2 = 6.54 moles x 44g/1 moles CO2 = 288g
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply