- In An Oscillating Lc Circuit With C 89 6 Pf The Current Is Given By I 1 84 Sin 2030 0 545 Where T Is In Second 1 (19.37 KiB) Viewed 10 times
In an oscillating LC circuit with C = 89.6 pF, the current is given by i = (1.84) sin(2030 +0.545), where t is in second
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In an oscillating LC circuit with C = 89.6 pF, the current is given by i = (1.84) sin(2030 +0.545), where t is in second
In an oscillating LC circuit with C = 89.6 pF, the current is given by i = (1.84) sin(2030 +0.545), where t is in seconds, i in amperes, and the phase angle in radians. (a) How soon after t=0 will the current reach its maximum value? What are (b) the inductance Land (c) the total energy? (a) Number Units (b) Number i Units (c) Number Units