Q1 A parallel-plate capacitor has plates of area 0.2 m² and a separation of 0.9 cm. A battery charges the latest to a po

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Q1 A Parallel Plate Capacitor Has Plates Of Area 0 2 M And A Separation Of 0 9 Cm A Battery Charges The Latest To A Po 1 (31.67 KiB) Viewed 9 times

Q1 A parallel-plate capacitor has plates of area 0.2 m² and a separation of 0.9 cm. A battery charges the latest to a potential difference of 100 V and is then disconnected. A dielectric slab of thickness 9 mm and dielectric constant 2 is then placed symmetrically between the plates. (a) What is the capacitance before the slab is inserted? (b) What is the capacitance with the slab in place? (c) What is the free charge g before the slab is inserted? and (d) What is the free charge q after the slab is inserted? (e) What is the magnitude of the electric field in the space between the plates and dielectric before inserting the dielectric? (1) What is the magnitude of the electric field in the space between the plates and dielectric after inserting the dielectric? (g) With the slab in place, what is the potential difference across the plates?