T K V Vv 1 17 Ve 0 5401 5 41 Id 9 A 6 1 4 1 1 12 04 0 04957 0 00508 3p 8 7 1 1134 0 905 0 000 5 8 6 1 16 0 07408 0 001 1 (25.21 KiB) Viewed 81 times
t K V VV 1.17 Ve 0-5401 5 41 ID 9.a 6.1 4.1 1. 12:04 0-04957 0.00508 3p 8.7 1.1134 0.905 0.000 5. 8.6 1.16 0.07408 0.001265 ho 50 6.7 25 1. Bere 0.01918 0.002 Ang x 2.0.06705 Sample calculattica Vo = 4. V = 14.2 Voo-Vo = 14.a -4 = 10.a. Voo-Y+= 14.8 - 4.9 = 9.3. Voo Vo 10.a = 1.0969 Voo-VE 9-3 log Voo Vo Vor-VE log 1-0968 = 0.04013: K: 2.80 3 log Vos-VO Veo-VE t K-2-303 leng X0-04013 5 K: 0.01848
9. Tabulate the results in the following order: t.x, (a-x),x/(a-x) 10. Plot log V-vo/ Vo-Vt against t (min.) and find k from the slope of the curve which is equal k 2.303 log V-V V-V. Slopek/2.303 (min) 11. find the half time period of the reaction : 12 = In 2/k=0.693 /k
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