- 7 A Force F F T Y Acts On A Particle Of Unit Mass M 1 So That It Moves Along The Parabola C Given By R T 1 (537.76 KiB) Viewed 9 times
= 7. A force F = F(t,y) acts on a particle of unit mass (m = 1) so that it moves along the parabola, C given by r(t) =<
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= 7. A force F = F(t,y) acts on a particle of unit mass (m = 1) so that it moves along the parabola, C given by r(t) =<
= 7. A force F = F(t,y) acts on a particle of unit mass (m = 1) so that it moves along the parabola, C given by r(t) =< ä(t), y(t) >=< t2, 44 > where t is time. Using Newton's Second Law F = mdi, we may compute that até' F =< M(x, y), N(x, y) >=1<x"(t), y" (t) >=< 2, 12t2 >=< 2, 12x >. (a) Now that we have Ē, calculate the work done by Ē in moving the particle along C from (0,0) to (1,1). (Recall that the work W done by a force F on an object moving along the curve C given by r(t), a st s b is given by ScF. di = sa F (F(t)) - =""(t)dt = Sc Mdx + Ndy.) =