In the arrangement shown below, an object can be hung from a string (with linear mass density u = 0.00200 kg/m) that pas

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In The Arrangement Shown Below An Object Can Be Hung From A String With Linear Mass Density U 0 00200 Kg M That Pas 1 (135.12 KiB) Viewed 10 times

In the arrangement shown below, an object can be hung from a string (with linear mass density u = 0.00200 kg/m) that passes over a light pulley. The string is connected to a vibrator (of constant frequency f), and the length of the string between point P and the pulley is L = 2.10 m. When the mass m of the object is either 25.0 kg or 36.0 kg, standing waves are observed; no standing waves are observed with any mass between these values, however. Vibrator Р р m (a) What is the frequency of the vibrator (in Hz)? (Note: The greater the tension in the string, the smaller the number of nodes in the standing wave.) 600 x Note that the higher tension generates a greater wave speed which produces a larger wavelength and thus a smaller number of nodes on the string. Hz (b) What is the largest object mass (in kg) for which standing waves could be observed? 1296 You appear to have correctly calculated the mass using your incorrect result for the frequency from part (a). kg (c) What If? What would the linear mass density of the string have to be (in kg/m) if 36.0 kg is the largest mass for which standing waves are observed? kg/m (d) For what values of m (in kg) would standing waves with the next four higher numbers of nodes be observed in this case? = m2 kg = m3 kg m4 kg = m5 kg