3b). An iron ball of mass = 10 kg stretches a spring 9.81 cm downward. When the system is in static equilibrium, let the

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3b An Iron Ball Of Mass 10 Kg Stretches A Spring 9 81 Cm Downward When The System Is In Static Equilibrium Let The 1 (29.3 KiB) Viewed 12 times

3b). An iron ball of mass = 10 kg stretches a spring 9.81 cm downward. When the system is in static equilibrium, let the position of the ball be y = 0 as the origin Now if we pull down the ball an additional 14.00 cm, stop and then release the ball Neglect the mass of the spring and damping effect. Find the relationship of the ball position y with time t. How many cycles per minute will this mass-spring execute? You can put positive downward and negative upward. [10 marks for setting up the right differential equation with the initial conditions, 10 marks for solving the differential equation, 5 marks for the number of cycles [25 marks in total] Hints: You may want to use Euler equation: == = cosx + sinx e" = cosx - sinx