Determine the seccion W that satisfies the requisites below. Mmax = 24 KN-m Oy max = 250Mpa Factor of safety (FS) = 1.7

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answerhappygod
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Determine the seccion W that satisfies the requisites below. Mmax = 24 KN-m Oy max = 250Mpa Factor of safety (FS) = 1.7

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Determine The Seccion W That Satisfies The Requisites Below Mmax 24 Kn M Oy Max 250mpa Factor Of Safety Fs 1 7 1
Determine The Seccion W That Satisfies The Requisites Below Mmax 24 Kn M Oy Max 250mpa Factor Of Safety Fs 1 7 1 (41.23 KiB) Viewed 8 times
Determine The Seccion W That Satisfies The Requisites Below Mmax 24 Kn M Oy Max 250mpa Factor Of Safety Fs 1 7 2
Determine The Seccion W That Satisfies The Requisites Below Mmax 24 Kn M Oy Max 250mpa Factor Of Safety Fs 1 7 2 (118.78 KiB) Viewed 8 times
Determine The Seccion W That Satisfies The Requisites Below Mmax 24 Kn M Oy Max 250mpa Factor Of Safety Fs 1 7 3
Determine The Seccion W That Satisfies The Requisites Below Mmax 24 Kn M Oy Max 250mpa Factor Of Safety Fs 1 7 3 (118.78 KiB) Viewed 8 times
Determine the seccion W that satisfies the requisites below. Mmax = 24 KN-m Oy max = 250Mpa Factor of safety (FS) = 1.7 Escriba a este una de formato de la tai Nmax 2 KN -VA. • 1.1 T === 4 . = 1.1: RILE -- M NE ម A Mr. * - or H ++ REKOM 4. 1 RE FE MA 4- E- … -- = K + - NEM 330 L = * 15 A 40 1. +-+ 24 WE ៨៩ ៥ គឺ ៖ ពីដី ! 4 \ ៩៩៩ ៩ ៖ ៥៥៥ ៖ -រ៖ ឱក A | B | ម = ft អ| ន៖ ៩៤ ៩ ដែឌីឌី ឌីធីវី អន ៥ ៖ ៩ ៩៩៩ ៨៩៩ ៩៩ * -រកគី៖ គគង្គ និ៖ខ ៥ ខមិន ដឹងនិន។ K TE = 222 2 10 KMI, == ។ == INST u, T * OSIM 914 7.34 H = K 14 12 . | A → TH, 11 13
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