2. (20 marks) (50 marks) A building is to be built on a strip footing on a clay with an undrained shear strength of 50 k

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2. (20 marks) (50 marks) A building is to be built on a strip footing on a clay with an undrained shear strength of 50 k

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2 20 Marks 50 Marks A Building Is To Be Built On A Strip Footing On A Clay With An Undrained Shear Strength Of 50 K 1
2 20 Marks 50 Marks A Building Is To Be Built On A Strip Footing On A Clay With An Undrained Shear Strength Of 50 K 1 (60.83 KiB) Viewed 15 times
2 20 Marks 50 Marks A Building Is To Be Built On A Strip Footing On A Clay With An Undrained Shear Strength Of 50 K 2
2 20 Marks 50 Marks A Building Is To Be Built On A Strip Footing On A Clay With An Undrained Shear Strength Of 50 K 2 (60.83 KiB) Viewed 15 times
2. (20 marks) (50 marks) A building is to be built on a strip footing on a clay with an undrained shear strength of 50 kPa, effective stress shear strength parameters of ' = 35 and c = 0 kPa, and a unit weight above the water table of 20 kN/m. It is assumed that the water table is 3m below the existing ground level (a) For preliminary design, suggest a suitable depth D for the foundation. Give two reasons why you have chosen this depth. (b) Taking the depth D suggested above, and a width (8) that you consider suitable, use the partial factors for Eurocode 7 Design Approach 1 Combination 2 to calculate the ultimate bearing resistance in terms of The undrained resistance (6) The drained resistance. (c) The permanent loading from the building is 100 kN/m and the variable loading is 50 kN/m. Calculate the design vertical loading using the partial factors for Eurocode 7 Design Approach 1 Combination 2. By converting the line load to an area load using the width suggested above, compare the ultimate bearing resistance to the design vertical loading and comment on the suitability of the design. Aide memoire: Ultimate bearing capacities of soil under strip footings: 9x = (1 + 2) + (undrained conditions) que = Ne + YON + 0.5yNy (drained conditions) 79 -1.0. Yo = 1.3.4 = 1.25". Y = 1.25, and y. - 1.4 "applied to tano (30 marks) . Meyer 2 100 1000 Total marks for Question 2: 100 marks
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