Problem 2 Given the partial differential equation is Ou(x, t) a u(x, t) = 0.8 for 0

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Problem 2 Given The Partial Differential Equation Is Ou X T A U X T 0 8 For 0 X 1 And 0 T 0 04 At 22x 1 With Ini 1 (20.06 KiB) Viewed 11 times

Problem 2 Given the partial differential equation is Ou(x, t) a u(x, t) = 0.8 for 0<x< 1 and 0 <t<0.04 at 22x 1 with initial condition u(x,0) = f(x) = 5x – x3 for t = 0 and 0<x<1 = = And boundary conditions = u(0,t) = 0 for x = 0 and 0 <t<0.04 u(1,t) = 0 for x = 1 and 0<t<0.0.4 Manually, calculate the solution, (x, t), when t = 0.04 by using Ax = h = 0.2 and At = k = 0.02 using Crank Nicholson's method. You have to show all the detail of procedure. And summarize your results in the table format, as shown below. = * = 0.00 x = 0.20 X = 0.40 *4 = 0.60 As = 0.80 * = 1.00 Time(s) t = 0.00 ta = 0.02 to = 0.04