A 5 DOF spacecraft model consists of 3 planar rigid bodies as shown in class. The spacecraft is assumed to be located in
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A 5 DOF spacecraft model consists of 3 planar rigid bodies as shown in class. The spacecraft is assumed to be located in
DYNAMICS OF A 3 BODY SPACECRAFT l l Bus LEFT SOLAR PANEL Rihy SOLAR PANEL N THICROP τ THIN ROD ( CL 08=CB CR ļ Kd د لا n2 Mp = 125 kg a ਹੈ , 4 SAME FOR BOTH PANELS Mo = 2250 kg Ip = 1000 Kg - m2 About CL, CR Io = 2000 Kg.² ABOUT CB l Im d = 6m FUNDAMENTAL fp = 0.1 Hz Free OF TRUEL к NCLUEET Dampal fp = 1 1 1 1 1 p0.25% & Brev
བ། (༦) Og(+) ATTITUDE УА) 9. ہے۔ x(+) M 1 9, = X, 92= Y, Z = 0, at = OL, 1s = OR SYSTEM MODEL HAS 5 DOF's (X,Y) TRANSATIONAL DOS's of Bus (m Og ATTiTvorog Sus (8C, ! ORIONTATION OF To Wan Arrays RELATIUT TO BUS
以 DX LOVERALIZED FORCOS 是 張) 击港 磅) - by - 以 09 二 |Qe 4 是( ) () 0 A| 决、 dt 00 00) ()- : - 0 00g 0px
A. A = 1112 : L = T-u THAT + + - PANEL Т. our = 1/2 Me" Ź Tous ūo. T = Tous TRIGHT PAWEL -MBMB. LCB V + TRANSITIONAL TRICHT {mpovca v R + < Ip Mwa. Mam ROTATIONAL žmp Tante tek wat Roti TOML NOR PANEL = Thiu TIUNIL THAT به ) + ماهه V - PANEL Trauho TIONAL ROTATIONAL
2 Un = xo 2 → ✓ + 12 KOR ? ♡ SYS STRAIN ENELY OF LOFT PANEL STRIN ENERLY OF RIGHT PANEL K tx y mo U = 1 kx² mm STRAN ENERLY OF LINEAR SPRING
ISBL L = 2 Mo (x² + y2) + + IB0? (4 +į mf6z+y+ +1*65* +++ (09 +61)* + 2 týdestij) Sol) + 1 / mp (2010 (66 +61) Col -ady los tor) CBL). +1 mp (*?**? +420g? to listo- 24ě légtör) SoR) + limp 12:46g (igt be cox + 2 dy fyt bie) Com) + 1/2 Ip loo ton )2 + 2 Ip (os + O2)2 - (Eko? + KO) 호 ,? ISBR B 2 where CALAC (89+OL) Soles (ty+ OL) SBR & slegton) Con & C(OBT OR)
PROJECT 1 1. DERIVE L 2. SUBSTITUTE L INTO ALL 5 LAGRANLE'S EQUATIONS GIVEN IN CLASS ON 5/3 PERFORM ALL DERIVATIVE IN ALL 5 EQUATIONS. AFTER STEP 2 LET) DEOM'S) CALCULATIONS
3. MATLAB SIMULATION Otom's PLUGIN NUMBERS HERE CODE МАТИ, (әре Plots / V LENERATE
TOTAL POWER GENERALIZED FORCES ✓ NB V Fous, ant & Mous, ant" + EXT Nu . BUSEXT Psys = + Friday HUR + + RIGHT PR Por, XT PAR, EXT w + FLEFT vo MONT NE? Patur, EXT Mv8 = x PAR, EXT vo 범 xñ + y nz Foun, dar = F in try bez , , Mous, Ext = Thz وحم NB = Of û ng M
こ n A ^ Mows, on tâng. oe nis = tör WEB THB I bo by b3 ceg -Sog ni | SOB Copo ng 10 0 0 1 Fous, ixt = Fx (cop hi ) F7 (se mit eine) = (FX COB - Fysos) + (EXSOB + Fy (98)ůz (kmi ýine) [(fx@p-Fy sepni + (tayan ng - 끼 +
= (fy 10, - Ғуло) х + (F30, + fy @s ) у Ө0) Qy вх и. X5 + + Р. (7 хо, -50, ) х + (fү 50, +hy 10 ) + те, + рік не бу фър 1 , а 1 Oo QORT две QOL о QozF - с |x| (+ | Q, Pz cob - у в (н (ву - 1 750 , +7 (6)
+ À Å. B = (A x ñ + Ayaz ). (Bx M + hym Axbx + Ay by n .^, = 1 ^2. ^2=1 A, ก, - 20
V Eom's FINAL PROJECT (iMaLL SOLAR KRLAY Rothens) M 9 + Ct D a + K9 = Q where 9 LOVERALIZED COORDINATE VECTOR 5x) M MASS MATRIX 5x5 (M=MT) NON-LWEAR ACCELERATION VECTOR 5x1 DAMPINL MATRIX 5x5 2 D-07) (kakt) a sxs STIFFNESS MATRIX k VI 11 LUMALIZE FORCE VE Ztore 5*) WE USUALLY PART THE LAUFALIZED (ory in 771 VECTOR AS LLOWS: х RIGID 31r У. OOPY DOG'S 92 B6 2) If 1 ELлс /FLх 5x1 2 DOF'S. 3 og 94
EÓM'S FINAL PROJECT (SMALL SOUTH ARKAY ANELTS 3 2 2 Z Mer of :: 0 o 0 O 010 PH KH 4 Merliner (Mb + 2 MP M6+ame TI + 2 Ip +2mp (8+)² J rumpaseo mp d sog Mr 're mp a cop -med cog 쓰 3x2 2 Ip + mpd (8+d) I, timp d (ord)] 3x3 0 T Ei क = M fra mit 2x3 2 x 2 Miff = (Ip tmp d² I 2x2 ) KIO 2x2 DER - [1], KTE KH = [tex] 2x2 impo{(og +01) - 0g + ón)?} COB modz (68 +0,1² - log + Onl?} soo 0 TOR Qx QY 9ra [] 96= [r BOB 2 2x 3x! 3x !