110 120 130 100 90 304 DB - 35.0000 deg C WB = 30.9498 deg C: RH-75.0000 % W27 1635 g/kg h=104.1604 kJ/kg: -0.9108 m3/kg

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110 120 130 100 90 304 Db 35 0000 Deg C Wb 30 9498 Deg C Rh 75 0000 W27 1635 G Kg H 104 1604 Kj Kg 0 9108 M3 Kg 1 (161.06 KiB) Viewed 11 times

Please explain how I want to visualize the actual desiccant
cooling system based of this psychometric chart? Please show in
picture if possible. Thank you.
110 120 130 100 90 304 DB - 35.0000 deg C WB = 30.9498 deg C: RH-75.0000 % W27 1635 g/kg h=104.1604 kJ/kg: -0.9108 m3/kg: SDP-29.8995 deg C: Nd - 1.0980 kg/m3, dm = 1.1278 kgimm3: AW -0.0298249 kg/m3; vp = 4239.9758 Pa -130 80 70 -120 20 Saturation temperature - deg C Enthalpy - kJ/kg(a) 110 20 -100 Po umidity ratio 20 Dehumid DB = 35,0000 deg C WB - 21.7552 deg ; RH-30.9612% w = 10.9332 kg: h-63 2490 kJkg: V=0.8881 m3.kg: DP - 15.3419 deg C: d = 1.1260 kg(am3 dm - 1.1383 kg/mm3 Cooling AW -0.0123110 kg/m3 vp - 1750.3278 Pa OB - 25.0000 deg ! WB - 18.6857 deg ; RH = 55.0000 %; W.10.9332 kg: h = 52.9847 kJ/kg v=0.8592 m3/kg; DP - 15.3419 deg C; d - 1.1639 kgfam3 dm - 1.1766 kg ( mm3 AW -0.0127249 kg/m3; vp - 1750 3278 Pa -90 10. 80 Volume - cu.mk .m/kg(a) -10 -70 un -20 -10 -20 -10 30 40 50 10 20 Dry bulb temperature - deg C