= а 7. Given a QPSK signal vopsk(t) = 2b(t)sin(211 x 105t) + 2be(t)cos(21 x 105t) where bo(t), be(t) take a value of -1

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= а 7. Given a QPSK signal vopsk(t) = 2b(t)sin(211 x 105t) + 2be(t)cos(21 x 105t) where bo(t), be(t) take a value of -1 or 1 every 6 seconds. For Vopsk(t), determine (1) (5%) signal power Ps; (2) (5%) symbol period T, and bit period Tb; (3) (5%) nominal bandwidth BQPk; (4) (5%) energy per symbol Es and energy per (5) (5%) minimum distance between symbols dQpskº bit Eb;