= - = = = 5. (10%) Consider a signal v(t) = b(t)cos?(Wot + o). As in the figure, b(t) = bk for t E ((k – 1)Ty, kto] and
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= - = = = 5. (10%) Consider a signal v(t) = b(t)cos?(Wot + o). As in the figure, b(t) = bk for t E ((k – 1)Ty, kto] and
= - = = = 5. (10%) Consider a signal v(t) = b(t)cos?(Wot + o). As in the figure, b(t) = bk for t E ((k – 1)Ty, kto] and bk = 1,-1,-1,1 for k = 1,2,3,4 with 1/Ty « fo. v(t) passes through an integrator that takes integration on v(t) for 1 every Ty seconds and outputs vo(kTb) for k = 1,2,3,4. Determine v.(ktb) for k = 1,2,3,4 with your derivations. ( = = b(t) 4 -1 1 1 -1 0 2. 4 3 t(To) 1
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