A segmented memory has paged segments. Each virtual address has a 2-bit segment number, a 2-bit page number, and an 11-b

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

A segmented memory has paged segments. Each virtual address has a 2-bit segment number, a 2-bit page number, and an 11-b

Post by answerhappygod »

A Segmented Memory Has Paged Segments Each Virtual Address Has A 2 Bit Segment Number A 2 Bit Page Number And An 11 B 1
A Segmented Memory Has Paged Segments Each Virtual Address Has A 2 Bit Segment Number A 2 Bit Page Number And An 11 B 1 (50.72 KiB) Viewed 41 times
A segmented memory has paged segments. Each virtual address has a 2-bit segment number, a 2-bit page number, and an 11-bit offset within the page. The main memory contains 32 KB, divided into 2-KB pages. Each segment is either read-only. read/write, or read/writelexecute. The page tables and protection are as follows: Segmento Segment 1 Read only Segment 2 Segment 3 Read/Write/Execute Read/Write Read only Virtual Page Virtual Page Virtual Page Virtual Page Page Frame Page Frame Page Frame Page Frame 0 0 0 On disk 0 13 1 1 1 1 5 Page Table not in main 2 On disk 2 9 2 2 memory 3 11 3 6 3 On disk 10 For each of the following accesses to virtual memory, tell what physical address is computed.If a fault occurs, tell which kind. Access Segment Page Offset within page 1. branch to it 1 2 0 2. fetch data 1 33 3. fetch data 3 1023 4. store data 4 5. store data 2 0 6. store data 3 14 7. branch to it 3 7 8. fetch data 80 9. fetch data 2 4 10. fetch data 55 ONOOON-W OON w WowWN
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply