RC RB1 B1 -+ Collector Base Q1 2N3904 D1 Emitter RE = B1 RB1 RE RC D1 Q1 20V 3k 800 3k VZ: 3.3V NPN BJT

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

RC RB1 B1 -+ Collector Base Q1 2N3904 D1 Emitter RE = B1 RB1 RE RC D1 Q1 20V 3k 800 3k VZ: 3.3V NPN BJT

Post by answerhappygod »

Rc Rb1 B1 Collector Base Q1 2n3904 D1 Emitter Re B1 Rb1 Re Rc D1 Q1 20v 3k 800 3k Vz 3 3v Npn Bjt 1
Rc Rb1 B1 Collector Base Q1 2n3904 D1 Emitter Re B1 Rb1 Re Rc D1 Q1 20v 3k 800 3k Vz 3 3v Npn Bjt 1 (49.93 KiB) Viewed 40 times
For the following problem assume the current through the base in
equal to zero.
Find the currents through the emitter (I_E) and collector
(I_C)
Find the voltage at the emitter (V_E) and collector (V_C),
find the voltage from base to emitter (V_BE) and base to
collector (V_BC)
RC RB1 B1 -+ Collector Base Q1 2N3904 D1 Emitter RE = B1 RB1 RE RC D1 Q1 20V 3k 800 3k VZ: 3.3V NPN BJT
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply