- Problem Statement The Figure Below Depicts The Velocity Control Structure For An Industrial Conveyor Belt Where Velocit 1 (81.64 KiB) Viewed 42 times
- Problem Statement The Figure Below Depicts The Velocity Control Structure For An Industrial Conveyor Belt Where Velocit 2 (97.24 KiB) Viewed 42 times
Using the information provided above, please explain how this
solution below was achieved, and if it was an accurate
solution.
- Problem Statement The Figure Below Depicts The Velocity Control Structure For An Industrial Conveyor Belt Where Velocit 3 (52.57 KiB) Viewed 42 times
With the constant parameters K, and K, a closed-loop transfer function for the velocity control system was first derived. By combining the controller, power amplifier, and conveyor dynamics into one simple expression, G(s), the velocity control structure shown in Figure 1 can be simplified as the following: 10 Given that G (s) 324971Kand K, are constant parameters, pwr G (s) plant $+10 + K G(s) = (K, +) K P pwr (S)G (s) plant 250(K S+K) s(s+10)(+1) 250(K S+K) s +11s +10 Equation 1 The following is the formula for calculating a closed loop transfer function VC(s), where N(s) is the numerator and D() is the denominator: V() Va(s) CL V. (S) N(S) D(3) N(S) D(S) + N(S) Equation 2 CL = The closed loop transfer function V (s) can be defined as follows using the formula for a closed loop transfer function of the previous equation: V(s) Vc(s) 2500K $ +K) s+115'+ (10+250K)s + 250K Equation 3 V (5) P
2. (15 pts) Develop and specify a Routh table for the CL system. Provide values in decimal format with only up to 3-decimal places of numeric precision. Our team generated a Routh table for the closed loop system after deriving the closed loop transfer function of the velocity control system: s3 1.000 250K + 10 P ي s? 11.000 250K 4 s' 250K p 22.73K, + 10 0 sº 250K 0 Table 1: Routh table for the CL system