225 Mi 60 Hz 138 Kv Transmission Line Has Per Phase R 0 169 2 Mi L 2 093 Mh Mic 0 01427 Uf Mig 0 Find V And I At 1 (117.01 KiB) Viewed 31 times
Hi how did they get y to be5.383*10^-6?
and also how did they get -18.195?
225 mi, 60 Hz, 138 kV transmission line has per phase : r= 0.169 2/mi l = 2.093 mH/mic=0.01427 uF/mig=0 Find V and I at the sending end of the line for 40 MW load with 0.95 lagging pf at 132 kV. |VR|= 132x103/13 = 76.2 ZVR = 0 / P =184.1 ZIR =-18.1959 3|V2|0.95 z=0.169+ j0.789; (y = j5.383x10-6 Finding T: Z Z. = = 387.32-6.05° y1 = 225, zy = 0.4688Z83.95° = y sinh hl=.452284.4° cosh yl = .8950Z1.42° =
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