NOTE FOR EXPERTS: THERE ARE MANY ANSWERS UP ON answers FOR VARIATIONS OF THIS QUESTION. THERE ARE DIFFERENT NUMBERS OF X,

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answerhappygod
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NOTE FOR EXPERTS: THERE ARE MANY ANSWERS UP ON answers FOR VARIATIONS OF THIS QUESTION. THERE ARE DIFFERENT NUMBERS OF X,

Post by answerhappygod »

NOTE FOR EXPERTS:
THERE ARE MANY ANSWERS UP ON answers FOR VARIATIONS OF THIS
QUESTION. THERE ARE DIFFERENT NUMBERS OF X, V AND W IN EACH
QUESTION SO PLEASE ANSWER THIS QUESTION SPECIFICALLY MANUALLY AND
NOT COPY PASTE SOLUTIONS FROM ANOTHER VARIATION OF THIS QUESTION.
THANKS
Note For Experts There Are Many Answers Up On Chegg For Variations Of This Question There Are Different Numbers Of X 1
Note For Experts There Are Many Answers Up On Chegg For Variations Of This Question There Are Different Numbers Of X 1 (38.88 KiB) Viewed 38 times
Call a string of letters "legal" if it can be produced by concatenating (running together) copies of the following strings: 'U','ww', 'xx"yyy' and 'zzz'. For example, the string 'xxuu' is legal because it can be produced by concatenating' xx','U' and 'u', but the string 'xxxu' is not legal. For each integer n > 1, let to be the number of legal strings with n letters. For example, t1 = 1 ('u' is the only the legal string). t2 = 13 = in = a tn-1 + b1,-2 + ctn-3 for each integer n > 4 = where a = b= and c =

For each integer n > 1, let pn be the number of legal strings with n letters that also read the same right to left as they do left to right (like 'xxuxx', for example). Which of the following expressions is equal to P101? P50 + P49 Ot50 + 148 Otso + 2t49 OP100 + P99 P50 + 2p49 Ot50 + 149 Ot50 + 2t48 Ot100 + t99
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