A uniform disk with mass 41.1 kg and radius 0.250 m is pivoted at its center about a horizontal, frictionless axle a tha

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A uniform disk with mass 41.1 kg and radius 0.250 m is pivoted at its center about a horizontal, frictionless axle a tha

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A Uniform Disk With Mass 41 1 Kg And Radius 0 250 M Is Pivoted At Its Center About A Horizontal Frictionless Axle A Tha 1
A Uniform Disk With Mass 41 1 Kg And Radius 0 250 M Is Pivoted At Its Center About A Horizontal Frictionless Axle A Tha 1 (25.42 KiB) Viewed 37 times
A Uniform Disk With Mass 41 1 Kg And Radius 0 250 M Is Pivoted At Its Center About A Horizontal Frictionless Axle A Tha 2
A Uniform Disk With Mass 41 1 Kg And Radius 0 250 M Is Pivoted At Its Center About A Horizontal Frictionless Axle A Tha 2 (21.21 KiB) Viewed 37 times
A Uniform Disk With Mass 41 1 Kg And Radius 0 250 M Is Pivoted At Its Center About A Horizontal Frictionless Axle A Tha 3
A Uniform Disk With Mass 41 1 Kg And Radius 0 250 M Is Pivoted At Its Center About A Horizontal Frictionless Axle A Tha 3 (23.57 KiB) Viewed 37 times
A uniform disk with mass 41.1 kg and radius 0.250 m is pivoted at its center about a horizontal, frictionless axle a that is stationary. The disk is initially at rest, and then a constant force 26.5 N is applied tangent to the rim of the disk.
Part A What is the magnitude v of the tangential velocity of a point on the rim of the disk after the disk has turned through 0.400 revolution? Express your answer with the appropriate units. μΑ ? ? m v = 1.11 S Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining
Part B What is the magnitude a of the resultant acceleration of a point on the rim of the disk after the disk has turned through 0.400 revolution? Express your answer with the appropriate units. НА BUT ? m a e 3.99 sa Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining
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