(3)
can you solve with details please asap(((b)))
226 Ra Ква =0 PRA = 0 Example 43.7: The Energy Liberated When Radium Decays Before decay KRO Ka 86 The 226 Ra nucleus undergoes alpha decay. (A) Calculate the Q value for this process. The masses are 226.025 408 u for 226 Ra, 222.017 576 u for 222Rn, and 4.002 603 u for He. 222 RA PRn After decay Pa (B) What is the kinetic energy of the alpha particle after the decay?
226 Ra Ква =0 PRA = 0 Example 43.7: The Energy Liberated When Radium Decays Before decay KRO Ka 86 The 226 Ra nucleus un
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226 Ra Ква =0 PRA = 0 Example 43.7: The Energy Liberated When Radium Decays Before decay KRO Ka 86 The 226 Ra nucleus un
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