A neutron moves along the path y? = 5x for r > 0 ft. At x = 3 ft, the particle has horizontal components of velocity and

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answerhappygod
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A neutron moves along the path y? = 5x for r > 0 ft. At x = 3 ft, the particle has horizontal components of velocity and

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A neutron moves along the path y? = 5x for r > 0 ft. At x = 3 ft, the particle
has horizontal components of velocity and acceleration equal to V = 6 ft/s and ax =-2 ft/s?.
a) What is the neutron's speed when it reaches r =3 ft?
b) What is the magnitude of the neutron's acceleration when it reaches r = 3 ft?
the path is y^2 = 5x instead of y?=5xthere is no picture given
there is no picture given
A Neutron Moves Along The Path Y 5x For R 0 Ft At X 3 Ft The Particle Has Horizontal Components Of Velocity And 1
A Neutron Moves Along The Path Y 5x For R 0 Ft At X 3 Ft The Particle Has Horizontal Components Of Velocity And 1 (38.42 KiB) Viewed 28 times
A Neutron Moves Along The Path Y 5x For R 0 Ft At X 3 Ft The Particle Has Horizontal Components Of Velocity And 2
A Neutron Moves Along The Path Y 5x For R 0 Ft At X 3 Ft The Particle Has Horizontal Components Of Velocity And 2 (38.42 KiB) Viewed 28 times
(4275x) (5 1x) = (51(6 fts) = 130ft = SYTISH (546) + (0)(x) = (5)(-2) = FIO E 2. Total - 8 points) A neutron moves along the path y2 = 5x for x20 ft. Atx= 3 ft, the particle has horizontal components of velocity and acceleration equal to vx = 6 ft/s and ax=-2 ft/s2. a) (4 points) What is the neutron's speed when it reaches x = 3 ft? y² = 5x Vy=6fths = x 9x=-2ft/= ☆ V = ? S = 3ft x) 52√10 = 315 B15227 b) (4 points) What is the magnitude of the neutron's acceleration when it reaches x = 3 f?
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