A solution is made which contains 0.10M Cd+2 and 0.50M NH3. As a result the complex ion Cd(NH3)4+2 forms. What will be t

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answerhappygod
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A solution is made which contains 0.10M Cd+2 and 0.50M NH3. As a result the complex ion Cd(NH3)4+2 forms. What will be t

Post by answerhappygod »

A solution is made which contains 0.10M Cd+2 and
0.50M NH3. As a result the complex ion Cd(NH3)4+2 forms. What will
be the concentration of free Cd+2 ions in this
solution?
Cd+2 + 4NH3 = Cd(NH3)4+2

Kf = 1.7 x 107
Can someone explain this really specifically? I am so
lost right now
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