2.) Samantha took a 45.0g cube of solid H20 (an ice cube) out of the freezer at -5.00°C and put it on the table in the l

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answerhappygod
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2.) Samantha took a 45.0g cube of solid H20 (an ice cube) out of the freezer at -5.00°C and put it on the table in the l

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2 Samantha Took A 45 0g Cube Of Solid H20 An Ice Cube Out Of The Freezer At 5 00 C And Put It On The Table In The L 1
2 Samantha Took A 45 0g Cube Of Solid H20 An Ice Cube Out Of The Freezer At 5 00 C And Put It On The Table In The L 1 (25.06 KiB) Viewed 37 times
2 Samantha Took A 45 0g Cube Of Solid H20 An Ice Cube Out Of The Freezer At 5 00 C And Put It On The Table In The L 2
2 Samantha Took A 45 0g Cube Of Solid H20 An Ice Cube Out Of The Freezer At 5 00 C And Put It On The Table In The L 2 (16.59 KiB) Viewed 37 times
2.) Samantha took a 45.0g cube of solid H20 (an ice cube) out of the freezer at -5.00°C and put it on the table in the lab. The ice cube melts by absorbing heat from the air in the room, which changes slightly, but to four significant figures is at a constant 20.00°C, and the melt-water reaches room temperature. (Cice 2050 J/kgCº, LF = 3.33x10 J/kg, cw = 4180 J/kgCº) (Hint: don't forget to convert to Kelvin in appropriate places.) czwa) Start with AS = 94 to find the total change in entropy for the H2O for this entire process.
b) Start with AS = $ 4. to find the change in entropy for the air for this entire process. = c) Find the total change in entropy for the universe for this process.
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