Calculate the pH at the equivalence point when 75.0 mL of 0.250 M HCl is mixed with 0.350 M of CH3NH2. Kb = 4.4 x 10-4 Y

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answerhappygod
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Calculate the pH at the equivalence point when 75.0 mL of 0.250 M HCl is mixed with 0.350 M of CH3NH2. Kb = 4.4 x 10-4 Y

Post by answerhappygod »

Calculate the pH at the equivalence point when 75.0 mL of 0.250
M HCl is mixed with 0.350 M of CH3NH2. Kb = 4.4 x 10-4
Your answer must include a balanced equation for the new
equilibrium established, completed ICE box and assumption
check.
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