4.2 X An enzyme has a Km value of 3.5 x 10-3 M and is inhibited by a competitive inhibitor | (Ki is 4 x 10-5 M). The sub

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4 2 X An Enzyme Has A Km Value Of 3 5 X 10 3 M And Is Inhibited By A Competitive Inhibitor Ki Is 4 X 10 5 M The Sub 1 (39.86 KiB) Viewed 49 times

4.2 X An enzyme has a Km value of 3.5 x 10-3 M and is inhibited by a competitive inhibitor | (Ki is 4 x 10-5 M). The substrate concentration is 5 x 104 M. 4.2.1 How much of the inhibitor is needed for 65% inhibition? 4.2.2 How much does the substrate concentration have to be increased to reduce the inhibition to 35%? (6) (6) 4.3 What concentration of substrate (in terms of the Km value) is required to achieve % of the maximal velocity? (6) 4.4. The Vmax of an enzyme is determined to be 65 x 103 mM.min', using an [E] of 2.0 x 10-3mM. Given that Vmax = kcat [E]: 4.4.1 Calculate kcat. Make sure to designate the correct units. 4.4.2 How much time does it take for a single reaction to occur? (2) (2) TOTA rool