(A) At point a phenol is 24 (0/0) % of System = 36 Total weight = 36 gon Amount of phenol = 0.24*36 = = 8.64 gram Amount

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A At Point A Phenol Is 24 0 0 Of System 36 Total Weight 36 Gon Amount Of Phenol 0 24 36 8 64 Gram Amount 1 (123.74 KiB) Viewed 44 times

A At Point A Phenol Is 24 0 0 Of System 36 Total Weight 36 Gon Amount Of Phenol 0 24 36 8 64 Gram Amount 2 (123.74 KiB) Viewed 44 times

Please I need to solve question 2
Don't solve question 1 because I add the answer of that
Just solve question 2
Thank you
(A) At point a phenol is 24 (0/0) % of System = 36 Total weight = 36 gon Amount of phenol = 0.24*36 = = 8.64 gram Amount of water = 0.76*36 = 27.36 gram (32 At point of phenol concentration is 50% % Total weight of System = 100 g Amount of phenol = 0.5 +100 - 50g Amount of water = 0.5*100 sog (c) At point f system is separated into Equal weight of water reh and phend sich. Here pheno) concentration isot (wo) Amount of water = 045*36 = 189 Amount of phenol = 0.5*36 =189
(A) At point a phenol is 24 (0/0) % of System = 36 Total weight = 36 gon Amount of phenol = 0.24*36 = = 8.64 gram Amount of water = 0.76*36 = 27.36 gram (32 At point of phenol concentration is 50% % Total weight of System = 100 g Amount of phenol = 0.5 +100 - 50g Amount of water = 0.5*100 sog (c) At point f system is separated into Equal weight of water reh and phend sich. Here pheno) concentration isot (wo) Amount of water = 045*36 = 189 Amount of phenol = 0.5*36 =189