The combustion of butane proceeds according to equation 2C4H10 + 13O2 → 8CO2 + 10H2O. The enthalpy change of this proces

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answerhappygod
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The combustion of butane proceeds according to equation 2C4H10 + 13O2 → 8CO2 + 10H2O. The enthalpy change of this proces

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The combustion of butane proceeds according to equation 2C4H10 + 13O2 → 8CO2 + 10H2O. The enthalpy change of this process is –2877.0 kJ/mol. Use the following from Hess’s law and calculate the enthalpy of formation of 1 mol of butane, if ΔH f (CO2) = −393.5 kJ/mol,
ΔH f (H2O) = −241.8 kJ/mol, ΔH f (O2) = 0.
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