Physics 131 Exam 2 SP22 Show pertinent work for credit Assume given quantities to be accurate to at least 3 significant

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Physics 131 Exam 2 SP22 Show pertinent work for credit Assume given quantities to be accurate to at least 3 significant

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Physics 131 Exam 2 Sp22 Show Pertinent Work For Credit Assume Given Quantities To Be Accurate To At Least 3 Significant 1
Physics 131 Exam 2 Sp22 Show Pertinent Work For Credit Assume Given Quantities To Be Accurate To At Least 3 Significant 1 (42.34 KiB) Viewed 63 times
Physics 131 Exam 2 Sp22 Show Pertinent Work For Credit Assume Given Quantities To Be Accurate To At Least 3 Significant 2
Physics 131 Exam 2 Sp22 Show Pertinent Work For Credit Assume Given Quantities To Be Accurate To At Least 3 Significant 2 (33.22 KiB) Viewed 63 times
Physics 131 Exam 2 SP22 Show pertinent work for credit Assume given quantities to be accurate to at least 3 significant figures Circle your answers and be sure to include proper units 1. A 3.00 kg mass is initially at rest upon a horizontal surface. A rope is tied to one end and pulls in the -i direction with a constant force of 20.0 N. An applied force acts on the mass, pulling at an angle of 15.0° with respect to the positive x-direction as shown below. ME = 3kg 35N - 2012 4 is a) If the magnitude of the applied force is 35.0 N and the system is frictionless, what is the acceleration of the mass? 27-200 + 35 15º = ma 33.8094 20 4950515 3 14.4025 misal b) If the system is frictionless, what must the magnitude of the applied force be if the net force acting on the mass is equal to zero? - 20N & Papp = 0 20 + Tapp cos 15-0 Happ= 20 Cors 20.706N
c)If the magnitude of the applied force is 35.0 N and the system is not frictionless, what is the acceleration of the mass if the coefficient of kinetic friction is 0.6007 in mg -3()39,41 x fx = MR Fn = 29.4 (0.600) - 17.64N - Pour - ON Mx . F 395.000 15 -200 -17.CHN - 3a 3 39 la=-1.28 ml as² d) If the acceleration produced is to be 1.50 m/si and the coefficient of kinetic friction is 0.600, what should the magnitude of the applied force be? Assume that it remains acting at 2005 a 50 ml My = 0.600 SF - Fapp cas 15-17.14 - 201 = (1.50) It - Fapples 15° -37.64 = 4.5 - Tapp = ? Fapp cas75 -4.5+ 37.64 000 15 couts Tapp = 43.630
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