A square coil of side d=8.40 cm and N=120 turns is outside a constant and uniform magnetic field of magnitude B=1.70 T.

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answerhappygod
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A square coil of side d=8.40 cm and N=120 turns is outside a constant and uniform magnetic field of magnitude B=1.70 T.

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A square coil of side d=8.40 cm and N=120 turns is outside a
constant and uniform magnetic field of magnitude B=1.70 T. The
field is perpendicular to the plane of the coil, as shown in the
figure. If the coil is pulled in at constant speed v, that is, the
net force is zero (Fnet=0) and the coil is not accelerating; the
time it takes to move the coil from ''completely out'' to
''completely in'' the field is Δt=0.11 s. The coil has a total
resistance of R = 84 Ω.
a) What is the area with magnetic field enclosed by the coil at
the beginning of the problem (A(t=0))? and the magnitude of
magnetic flux (ΦB(t=0))?
b) What is the speed of the coil?
c) ¿Cuál es la fórmula (en letras) del área con campo magnético
encerrado por la bobina como función del tiempo (A(t)) en términos
de d,v y t? in
letters
d) What is the value of the induced current?
A Square Coil Of Side D 8 40 Cm And N 120 Turns Is Outside A Constant And Uniform Magnetic Field Of Magnitude B 1 70 T 1
A Square Coil Of Side D 8 40 Cm And N 120 Turns Is Outside A Constant And Uniform Magnetic Field Of Magnitude B 1 70 T 1 (33.58 KiB) Viewed 62 times
CAPA Prom Una bobina cuadrada de lado de 8.40 cm y N-120 vueltas está fuera de una campo magnético constante y uniforme de magnitud #1.70 . El campo està perpendicular al plano de la bobina, tal como se muestra en la figura. Si se tira de la bobina hacia dentro a velocidad constante v, es decir, la fuerza neta es cero Freta) y la bobina no está acelerando; el tiempo que toma en mover la bobina de completamente fuera" a "completamente dentro del campo es -0.11 s. La bobina tiene una resistencia total de R 84 a) Cuál es el área con campo magnético encerrado por la bobina al iniciar el problema (At-0)»? y la magnitud de flujo magnético (t-o? A(0) (0) - So Tries 0/99 b) ¿Cuál es la velocidad de la bobina? V SA Tries 0/99 accuál es la formula (en letras del área con campo magnético encerrado por la bobina como función del tiempo (ACE)) en términos de d. vyt? Act) (en letras) Tries 0/99 d)2Cuál es el valor de la corriente inducida? Magnitud: Sentido: so Tries 0/99 eycCuál es la magnitud de la fuerza Fext ejercida? Fext-
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