answer the following question using
the EXACT formulas provided (responses
with exact formulas get a positive rating):
Two electrons are shot out of a double-barreled particle accelerator to the right, one after the other, and move on parallel trajectories. The electron on the top trajectory is fired after the one on the bottom. The top electron is not affected by any outside fields. The bottom electron is affected by a uniform magnetic field, of 2.5T, that acts perpendicularly to the path of the electron. Both electrons begin at rest before being acted upon by a potential difference of 12 V. If the electrons are fired with a distance of 46600 nm of separation, will the electrons collide in a head-on collision after the electron on the bottom is impacted by the magnetic field? Show your work to earn full marks for your answer.
us = Ad v= 41 à At Vavg = Vi + Üz 2 HR FN FNET = ma F = mac a = 12 de = r(20f) a=r (9) , = 7, + át så = (***) At Ad = vt + At? så = vrat – zást 0,2 = v?+zaad -b + b2 - 4ac my2 F = r Fe = mr(2mef2 2лв Fe = mr x = 2a W = Fd W = Fcosed E, = magh = Ex = med Em = E, + Ex kx? E = : F = kx p = mv Ft = Ap 1 2 + + mių, + m2 2 = muut + m2 V zm. vt + amev? = m.vn ਉਸ movil та й + тъй, ū= my + m2 m-m m + m2 V + 2m m + 2 mu (m. + m) 2m m2 – m ū, = mi + m2 V + Gm,m2 F = kq192 Fg = r2 G = 6.67 x 10-11 Nm2/kg2 k = 8.99 x 10° Gmplanet g= 2 Fe = qe Gm = ע kaz E = r2 T ΔΕΕ = -φεΔd k9192 Eg = r V = Eg 9 AE =k4.92 ką,936, +) AEE ΔV = F = qvB sin e AV E=- Ad Fon wire = ILB sin e 15 ka V= mv T = qB
answer the following question using the EXACT formulas provided (responses with exact formulas get a positive rating):
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answer the following question using the EXACT formulas provided (responses with exact formulas get a positive rating):
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