Problem 2 (40 points) Light from a monochromatic source (a green laser?) with wavelength ly = 500 nm is incident on an o

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Problem 2 (40 points) Light from a monochromatic source (a green laser?) with wavelength ly = 500 nm is incident on an o

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Problem 2 40 Points Light From A Monochromatic Source A Green Laser With Wavelength Ly 500 Nm Is Incident On An O 1
Problem 2 40 Points Light From A Monochromatic Source A Green Laser With Wavelength Ly 500 Nm Is Incident On An O 1 (102.67 KiB) Viewed 67 times
Problem 2 (40 points) Light from a monochromatic source (a green laser?) with wavelength ly = 500 nm is incident on an opaque surface with two narrow parallel slits in it. The slits have an unknown spacing d. The interference pattern is projected on a semicircular screen a distance L »d from the slits as shown below. There is constructive interference on the perpendicular bisector of the line between the slits (@= 0) in the figure.) Semicircular screen 1 L 1 2 narrow slits (not shown) d = ?? Incident laser beam 2 = 500 nm (a) If the first point of constructive interference intensity maximum) as increases from zero occurs at the angle 0 = 30°, what is the slit spacing d? What is the path length difference Ar for the light from one slit compared to the other, and what is the phase difference Ao between the waves from the two slits? NOTE: In case you need to be reminded: sin 30º = 1 and sin 60º = (b) At what angle & would the next intensity maximum be found? What are Ar and Ao in this case? (c) How many intensity minima (destructive interference) are observed in the range 0 <0< 90°? Give expressions for the angles where each intensity minimum occurs (you may need to leave these in terms of the arcsin() function). Make a sketch corresponding to the figure above and show the approximate locations of these minima on your sketch. (d) Suppose that you wanted to increase the number of intensity minima observed in the range 0 <0 < 90° by one compared to what you found in Part (e) by changing the wavelength of the laser. If the new minimum appears at 6 = 90°, what would the new wavelength 1, have to be?
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