Part A Measurements of the radioactivity of a certain isotope tell you that the decay rate decreases from 8315 decays pe

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Part A Measurements of the radioactivity of a certain isotope tell you that the decay rate decreases from 8315 decays pe

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Part A Measurements Of The Radioactivity Of A Certain Isotope Tell You That The Decay Rate Decreases From 8315 Decays Pe 1
Part A Measurements Of The Radioactivity Of A Certain Isotope Tell You That The Decay Rate Decreases From 8315 Decays Pe 1 (71.46 KiB) Viewed 49 times
Part A Measurements of the radioactivity of a certain isotope tell you that the decay rate decreases from 8315 decays per minute to 3005 decays per minute over a period of 3.50 days. What is the half-life T1/2 of this isotope? Express your answer numerically, in days, to three significant figures. ► View Available Hint(s) ΟΙ ΑΣΦ E) ? T1/2 = days Submit Previous Answers X Incorrect; Try Again; 4 attempts remaining

The first quantitative description of the hydrogen spectrum was given by Johann Balmer, a Swiss school teacher, in 1885. By trial and error, he found that the correct wavelength 434.1 nm of each line observed in the hydrogen spectrum was given by * =R(-) where m' is a constant, later called the Rydberg constant, and n may have the integer values 3,4,5..... If 434.1 nm is in meters, the numerical value of the Rydberg constant (determined from measurements of wavelengths) is R = 1.097x107m1 Balmer knew only the four lines in the visible spectrum of hydrogen. Thus, the original formula was written for a limited set of values of re. However, as more techniques detect other regions of the spectrum were developed, it became clear that Balmer's formula was valid for all values of ne. The entire series of spectral lines predicted by Balmer's formula is now referred to as the Balmer series. Part A What is the wavelength of the line corresponding to n=5 in the Balmer series? Express your answer in nanometers to three significant figures. (n) = 434.1 nm Previous Answers Correct Correct answer is shown. Your answer 434 nm was either rounded differently or used a different number of significant figures than required for this part. Important: If you use this answer in later parts, use the full unrounded value in your calculations. Part B - After passing a grating, the 2nd order maximum of this light forms an angle of 44.0 relative to the incident light. What is the separation d between two adjacent lines on the grating? Unit is um = 106 m. Keep 3 or 4 digits after the decimal point. ΟΙ ΑΣΦ ? d= um Submit Request Answer Part C- How many lines per centimeter does tha grating have? 1cm=0.01m enter an integer View Available Hint(s) | ΑΣΦ B) ? number of lines per cm = lines per cm Submit
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