11. Draw the following vectors using the scale 1 cm - 50 km/h. Then draw the opposite vector of each vector from questio
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11. Draw the following vectors using the scale 1 cm - 50 km/h. Then draw the opposite vector of each vector from questio
11. Draw the following vectors using the scale 1 cm - 50 km/h. Then draw the opposite vector of each vector from question #2)(with tail starting from the origin) and state the direction as a true bearing and quadrant bearing. Resolve each vector from question #2 into its horizontal and vertical compo- nents.(nine marks) Scale Icm = 50 km/hr 20km/hr Im Ihr си 20cm a. 20 km/h on a bearing of 020° 50 50.4cm 7 1 N о given 0 = 20 20kmh TO w direction of tou bearing = = 360° -0 -0 V Sin 20 peut e = 20 in => Douche By true bearing = 360°-20º = 340 ° 16620 => It is in the fourth quadrant because divection of true bearing is equal to I 180-0 900-0 T S 2780 7W 360-0 MCV4U Lesson Assignment INT 20 = 18.79 km/h S 340" in 20 = 6.64 Page 2
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