A separately excited wound field DC motor operates with an armature supply voltage of 280 Volts. The field current suppl
Posted: Wed May 18, 2022 6:40 am
A separately excited wound field DC motor operates with an
armature
supply voltage of 280 Volts. The field current supplied to the
field windings is,
under normal operation, equal to ππ = 1.0 A, and the resulting
no-load speed
is 2100 rpm. The armature resistance is 1.0 ο, and the full-load
developed
torque is 22 Nm.
(i) Determine the value of the product πΎππ and the full-load
armature current ππ under the conditions described
above.
(ii) Determine the full-load speed of the motor in rpm under
the conditions described above.
.
(iii) If the field current is reduced to 0.9 A, but the
developed
torque remains unchanged, calculate the new full-load
speed of the motor in rpm. Hint: Assume that the field
flux ππis proportional to the field current ππ.
armature
supply voltage of 280 Volts. The field current supplied to the
field windings is,
under normal operation, equal to ππ = 1.0 A, and the resulting
no-load speed
is 2100 rpm. The armature resistance is 1.0 ο, and the full-load
developed
torque is 22 Nm.
(i) Determine the value of the product πΎππ and the full-load
armature current ππ under the conditions described
above.
(ii) Determine the full-load speed of the motor in rpm under
the conditions described above.
.
(iii) If the field current is reduced to 0.9 A, but the
developed
torque remains unchanged, calculate the new full-load
speed of the motor in rpm. Hint: Assume that the field
flux ππis proportional to the field current ππ.