A separately excited wound field DC motor operates with an armature supply voltage of 280 Volts. The field current suppl

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899604
Joined: Mon Aug 02, 2021 8:13 am

A separately excited wound field DC motor operates with an armature supply voltage of 280 Volts. The field current suppl

Post by answerhappygod »

A separately excited wound field DC motor operates with an
armature
supply voltage of 280 Volts. The field current supplied to the
field windings is,
under normal operation, equal to 𝑖𝑓 = 1.0 A, and the resulting
no-load speed
is 2100 rpm. The armature resistance is 1.0 , and the full-load
developed
torque is 22 Nm.
(i) Determine the value of the product πΎπœ™π‘“ and the full-load
armature current π‘–π‘Ž under the conditions described
above.
(ii) Determine the full-load speed of the motor in rpm under
the conditions described above.
.
(iii) If the field current is reduced to 0.9 A, but the
developed
torque remains unchanged, calculate the new full-load
speed of the motor in rpm. Hint: Assume that the field
flux 𝝓𝒇is proportional to the field current π’Šπ’‡.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply