Lorentz Force Law: 1. A proton has a velocity of ū = (4.33 x 106m/s)î when it encounters a magnetic field B (0.0288T)).

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answerhappygod
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Lorentz Force Law: 1. A proton has a velocity of ū = (4.33 x 106m/s)î when it encounters a magnetic field B (0.0288T)).

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Lorentz Force Law 1 A Proton Has A Velocity Of U 4 33 X 106m S I When It Encounters A Magnetic Field B 0 0288t 1
Lorentz Force Law 1 A Proton Has A Velocity Of U 4 33 X 106m S I When It Encounters A Magnetic Field B 0 0288t 1 (119.44 KiB) Viewed 35 times
please answer all parts for the question.
Lorentz Force Law: 1. A proton has a velocity of ū = (4.33 x 106m/s)î when it encounters a magnetic field B (0.0288T)). (a) What is the force, i on the proton due to the magnetic field? (b) What is the radius of the circular path the proton is now in? 202 y 107mis into
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