2) Example-3 -Analytically Determined Statistics for an RV Constant in Time Sample Functions: x(si) = z where z changes

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899604
Joined: Mon Aug 02, 2021 8:13 am

2) Example-3 -Analytically Determined Statistics for an RV Constant in Time Sample Functions: x(si) = z where z changes

Post by answerhappygod »

2 Example 3 Analytically Determined Statistics For An Rv Constant In Time Sample Functions X Si Z Where Z Changes 1
2 Example 3 Analytically Determined Statistics For An Rv Constant In Time Sample Functions X Si Z Where Z Changes 1 (51.18 KiB) Viewed 66 times
2) Example-3 -Analytically Determined Statistics for an RV Constant in Time Sample Functions: x(si) = z where z changes for each s (but not each t) with fz(z) = 1 for 0 Szsi a) Ensemble Average, E[X()) E[X(t)) = xfx, (x2) dx = x(0= $8 b) Ensemble Autocorrelation Function Rxx(t.e + 7) = E[xce.si)x(8 + 1,5) = 1 *ief, adx, Since the sample functions are constant with time, Xe+u = Xx Rxx(t.t + 1) = which is true for all time, t, and all offsets, c) Temporal Average, A[x(s)] Although X(t,s) randomly varies from Sample Function Sample Function, it is constant with time. This means that the time-average of a sample function is equal to any and all of its values over time: A[x(s.] = d) Temporal Autocorrelation Function, Rxx, (t,t + ) Rxx, (1,2 + ) = A[x(t, s.)x(t + 1,50)] Since the Sample Functions are constant with time: x(t.s)x(t + 1,5) = Therefore: Rxx, (t.t + 1) = Since Sample Functions are constant with time, every point is equal to the time average: A[x ($) Therefore: Rxx, (t.1 + 1) = e) Tests for Stationarity i) Wide Sense Stationary?: Yes. Both criteria met. (1) E[X(t)] = Constant?: E[X(t)) = 0.5, Passes. (2) Rxx(t.t + 7) = Rxx() for all t and T?: Rxx(t,t + 1) = 0.333 Does not depend on t. Passes. ii) Correlation Ergodic?: No, Both criteria fail (1) A[x(t. $0] = E[X(t)]?: {A[x(s)] is random from 0 to 1} + {E[x()) = 0.5). Fails. (2) Rxx(t.t+1,5) = Rxx(t.t + 1)2:{Rex, (t.t + 1) ==}} + {Rxx(t.t + 1) = 0.333), Fails.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply