I was not given degrees of freedom but believe you can figure it
out given that we have the number of genotypes
Question 4. You genotype a population of 100 individuals and identify 50AA, 40 Aa and 10 aa individuals. You determine the expected number of individuals in the population if the population was in Hardy Weinberg Equilibrum (part c) and perform a chi square test. Table 11.5 Chi-Square Probabilities 0.90 0.016 0.10 0.30 0.46 1.39 2.71 dr 1 2 3 + 5 6 7 2.37 0.93 0.004 0.10 0.35 0.71 1.15 164 2.17 2.73 3.33 3.94 4.58 5.23 5.89 6.37 7.26 0.70 0.15 0.71 1.42 2.20 3.00 3.83 4.67 5.33 6.39 7.27 8.15 9.03 9.9) 10.82 11.72 0.21 0.58 1.00 1.61 2.20 280 3:49 4.17 4.87 5.58 6.30 7.04 7.79 8.35 8 Probabilities 0.30 0.20 1.07 1.64 2.41 3.22 3.67 4.67 4.88 5.99 6.06 7.29 7.23 8.56 8.38 9.80 9.52 11.03 10.66 12.24 11.78 13.44 12.90 14.63 14.01 15.81 15.12 16.99 16.22 18.15 17.32 19.31 3.36 4.35 5.35 6,35 7:34 8.34 9.34 10.34 0.05 3.84 5.99 7.82 9.49 11.07 12.39 14.07 15.51 16.92 18.31 19.68 21.03 22.36 23.69 0.01 6.64 9.21 11.35 13.28 15.09 16.81 18.48 20.09 21.67 23.21 24.73 26.22 4.61 6.25 7.78 9.24 10.65 12.02 13.36 14.68 15.99 17.28 18.35 19.8) 21.06 22.31 9 10 11 12 13 14 15 0.001 10.83 13.82 16.27 18.47 20.52 22.46 2432 26.13 27.88 29.59 31.26 32.91 34.53 36.12 37.70 27.69 1234 13:34 14.34 25.00 29.14 30.58 d) You obtain a chi-square value of 0.22. Consult the chi-square table above and determine is the population in HWE? Use the drop down menus to choose the most accurate answer. The population (Select] in Hardy Weinberg Equilibrium; the probability is Select) than Select that the difference between the observed and expected is due to chance.
Question 4. You genotype a population of 100 individuals and identify 50AA, 40 Aa and 10 aa individuals. You determine t
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Question 4. You genotype a population of 100 individuals and identify 50AA, 40 Aa and 10 aa individuals. You determine t
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